The triangle pqr shown on the coordinate grid below is reflected once to map onto triangle p'q'r': triangle pqr drawn on a 4 quadrant coordinate grid with vertices p is at 7, 6. r is at 5, 2. q is at 3, 5. if vertex p' is at (7, −6), what are the coordinates of vertex r'? (5, −3) (3, −5) (3, −2) (5, −2)

If we notice points P and P', the transformation preserves every point along x direction and moves the point by twice its y-coordinate down along y direction.

So, point P moved from (7, 6) to (7, 6-12) = (7, -6).

Hence, point R (5, 2) would be moved to (5, 2-4) = (5, -2).

The correct option is 4. The coordinates of R' is (5,-2).

Step-by-step explanation:

It is given that after reflection the triangle P'Q'R' is an image of triangle PQR.

If the figure reflects across the x-axis then the x coordinate remains same but the sign of y-coordinate change.

If the figure reflects across the y-axis then the y coordinate remains same but the sign of x-coordinate change.

It is given that P(7,6) and P'(7,-6). Since the x coordinate remains same, therefore the figure PQR reflects across the x-axis.

The point is Q(3,5).

The point is R(5,2).

Therefore the coordinates of R' is (5,-2). Option 4 is correct.

what's that

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.