The depreciating value of a semi-truck can be modeled by y = ao(0.85)x, where y is the remaining value of the semi, x is the time in years, and it depreciates at 15% per year. an exponential function comes down from the positive infinity and passes through the points zero comma seventy-five thousand. the graph is approaching the x-axis. what is the value of the truck initially, ao, and how would the graph change if the initial value was only $65,000?

Step-by-step explanation:

Given that the  depreciating value of a semi-truck can be modeled by

Since it crosses (0,75000) we find that when x =0 y = 75000

Substitute to get

So equation would be

If initial value is changed to 65000, the y intercept would be shifted down to

65000.  The whole curve would be a bit vertical down than the previous curve.

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions