16x^2=9 using ax^2+bx+c=0 factor the left hand side of the equation into two linear factors

becomes  ( is implied)

To solve a quadratic like this we need to find two numbers that multiply to equal ac and add up to b. In this case, two numbers that multiply to equal -144 and add to equal 0. These two numbers are 12 and -12. Factor using these numbers.



And if you ever need to find x you would just find any value that would cause one of the two to equal 0. Since 0 times anything is still 0, this would work. These values would be 12 and -12. (12-12 = 0, -12+12 = 0)

Cbottom left is the correct one.