Given the exponential equation 4x = 64, what is the logarithmic form of the equation in base 10?

Step-by-step explanation:

Given the exponential equation 4^x = 64

To convert exponential equation into log equation we use the rule

b^x = a then log_b(a)=x

the base of exponent becomes the base of log equation

4^x = 64 becoes

WE need log with base 10, but we got log with base 4

USe change of base formula to get base 10

log_b(a)= log(a)/ log(b)

has log with base 10

answer:

a=9

step-by-step explanation: lmk if you need a explanation