An angle bisector of a triangle divides the opposite side of the triangle into segments of 5 cm and 3 cm long. a second side of the triangle is 7.6 cm long. find the largest and shortest possible lengths of the third side of the triangle. round answer to the nearest tenth of centimeter

Answer with explanation:

We will use angle bisector theorem to solve this problem.

Angle bisector theorem states that, the ratio of Adjacent sides containing the angle which is bisected is equal to the ratio of the segments where the angle bisector cuts the third side.

From the given Triangle

From the given information about the triangle, which is

   An angle bisector of a triangle divides the opposite side of the triangle into segments of 5 cm and 3 cm long. A second side of the triangle is 7.6 cm long.

So,third Side of the triangle =4.56 cm ----Shortest possible length

Or, third Side of the triangle =

    cm ----Largest possible length

what level of math? also i don't need to be paid if i can you.

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.