Margaret and alice play a game involving two fair-number cubes with faces labeled 1 through 6. if margaret tosses a sum of 6 on her next turn, she wins the game. otherwise, the game continues.

what is the probability that margaret will win on her next turn?
the answer is a fraction

Margaret will toss a sum of 6, if one of the following situations occurs:
1. The first cube is 1 , the second cube is 5 : sum 6.
2. The first cube is 2, the second cube is  4: sum 6.
3. The first cube is 3, the second cube is  3: sum 6.
4. The first cube is 4, the second cube is 2 : sum 6.
5.  The first cube is 5, the second cube is 1 : sum 6.
So, there are 5 possible situation that suit for Margaret.
The probability that Margaret will win is:
number of "good" situation/ number of all possible situations .
There are 24 possible situations, so the probability is: 5/24

The answer to your question is b’(16,14)