What is the probability that a point chosen at random in the given figure will be inside the larger triangle and outside the smaller triangle?

enter your answer, as a fraction in simplest form, in the box.
p(inside larger triangle and outside smaller triangle) =

Given:
Area of a triangle = (h*b) / 2

Area of smaller triangle = (4cm * 4cm) / 2 = 16cm² / 2 = 8 cm²
Area of larger triangle = (6cm * 10cm) / 2 = 60cm² / 2 = 30 cm²

30cm² - 8cm² = 22cm²

Probability that the point is inside the large triangle but outside the small triangle:

22cm² / 30cm² → 11/15 → 0.73 or 73%

Your answer should be 1/3. i hope i could ! good luck : )