point h is the midpoint of side fk.

for the triangles to be congruent by sss, what must be the value of x?

x =

- The value of x must be 6

Given:- ΔFGH and ΔKJH are congruent by SSS postulate such that GH=JH

and Point H is the midpoint of side FK.

⇒ FH=HK

As ΔFGH and ΔKJH

⇒ GF=JK  [congruence parts of two congruent triangles are equal]

⇒3x-2=2x+4

⇒3x-2x=4+2    [Add 2 and subtract 2x on the sides]

⇒x=6

Thus the value of x=6.

it has the same slope and a different y-intercept

hope this : )