The tickets in a box are numbered from 1 to 15 inclusive. if a ticket is drawn at random and replaced and then a second is drawn at random, what is the probability that the sum of their numbers is even?
a. 49/225
b. 1/2
c. 113/225
i think it is c but i don't

We know that two odd numbers make an even number and two even numbers make another even number. So out of the first choice you have a 7/15 chance of getting it even and an 8/15 chance of getting it odd. 

If you get the first one even, then the second one MUST also be even so you multiply 7/15 with itself. 

If you get the first one odd, then the second one MUST also be odd so you multiply 8/15 with itself as well. 

You should have: 

(7/15) x (7/15) 

and 

(8/15) x (8/15) 

By multiplying the top portions with each other and the bottom portions with each other you get: 

49/225 and 64/225 respectively. 

Add both fractions together to get your answer. 

Your answer should be (64+49)/225 = 113/225 

Your answer is 113/225. 

Well, it seams as if you were correct. The answer is c. 113/225. Hope this helped!

c. 113/225

29. because you will divide each number of months by 12 to find the number of years. which would mean, 5, 12.5, 16, 45, 50, 72.5. which is crazy. anyhow, i think you find the median in the middle. and yea hope your test goes good