The service-time distribution describes the probability p that the service time of the customer will be no more than t hours. if m is the mean number of customers serviced in an hour, then suppose a computer technical support representative can answer calls from 6 customers in an hour. what is the probability that a customer will be on hold less than 30 minutes?

Probability that a customer will be on hold less than 30 minutes is %

Step-by-step explanation:

Complete question is

The service-time distribution describes the probability P that the service time of the customer will be no more than t hours. If m is

the mean number of customers services in an hour, then

. a. Suppose a computer technical support representative can answer calls from 6 customers in an hour. What is the probability

that a customer will be on hold less than 30 minutes?

Solution -

Given the equation of probability -

Where m is the average number of customers served in an hour

and t is the total time

Now, in this case m is equal to 6 as technical support representative ia bale to answer calls from 6 customers in an hour

and time t minutes hours

Substituting the given values in above equation, we get -

Probability that a customer will be on hold less than 30 minutes is %

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3