Mathematics, 01.09.2019 00:30 weg5309
The volumes of two similar solids are 1331 m3 and 216 m3. the surface area of the larger solid is 324 m3. what is the surface area of the smaller solid?
Answers: 2
![\frac{V_{1} }{V_{2}}=\frac{216}{1331}=\sqrt[3]{\frac{216}{1331}}=\frac{6}{11}](/tpl/images/0216/3426/be723.png)
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The volumes of two similar solids are 1331 m3 and 216 m3. the surface area of the larger solid is 32...
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