If sin theta = sqrt(2/2), which could not be the value of theta?
-225 degrees
-45 degrees
-135 degrees
-405 degrees

The solution would be like this for this specific problem:

sin(θ°) = √(2)/2 

θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° − sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ 

360°*0 + 45° = 45° 
360°*0 + 135° = 135° 
360°*1 + 45° = 405° 

sin(225°) = -√(2)/2

225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta cannot be 225 degrees.

225° is not possible

Step-by-step explanation:

Given that

we have to choose the option which could not be the value of theta.

As sine is positive in second and fourth quadrant.

⇒

Also,

Therefore 225° is not possible

the answer to this question is in the pic

2

step-by-step explanation: