What is the perimeter of a square whose diagonal is 3 radical 2

a square is made up of 2 congruent right triangles with the same leg length. we use the Pythagorean theorem to find the length of one of these legs. a^2+b^2=c^2, but we know that the legs are equal in length, so we have 2a^2=(3rad2)^2

2a^2=9*2

a^2=9

a=3

square is made up of 4 of these, so 4*3=12

the perimeter is 12

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5

17.08

correct me if i am wrong.