At jefferson high school, a student takes 4 core classes a day. there are 6 different core classes offered. how many different combinations of classes are there? 12 combinations 15 combinations 24 combinations 10 combinations

Order does not matter so you would want to use the "n choose k" equation:

n!/(k!(n-k)!), where n=number of possible choices and k=number of selections

In this case:

6!/(4!(6-4)!)

6!/(4!*2!)

15

So there are 15 unique combinations of classes possible.

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