Asimple random sample of 1800 hospital patients admitted in a given year shows that 82.5% had an error on their medical bill. which interval is the 95% confidence interval for the percent of all the hospital's admitted patients admitted that year who had an error on their medical bill?

The answer is: 74 patients.

Step-by-step explanation:

If we have 1800 patients of which 82.5% have had an error in their medical bill

They are 1800 x 0.825 = 1485 patients.

If of those 1485 patients we obtain the 95% confidence interval, it would be equal to: 1485 x 0.95 = 1410.75, which would be rounded in 1411 patients.

The confidence interval between 1485 who had an error in their bill over 95%, would be equal to 1485 - 1411 = 74 patients.

The answer is: 74 patients.

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.

step-by-step explanation:

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