Ten dartboard targets are being painted as shown in the following figure. the radius of the smallest circle is 3in. and each successive, larger circle is 3in. more in radius than the circle before it. a “tester” can of red and of white paint is purchased to paint the target. each 8oz. can of paint covers 16ft2. is there enough paint of each color to create all ten targets? show your work

Let's figure out the area to paint on one target.
The area to paint in white is the middle circle.

Its area is therefore the area of a circle of radius 2*3in minus the area of the red circle inside, which is 3 in (see the attached picture).

Hence the area to paint is A=pi(2*3)^2-pi(3)^2=pi(36-9)=27pi sq in.
Using pi~3.14, A=84.78 square inches

One square inch is approximately 0.006944 square feet hence A=84.78*0.006944=0.5887 square feet.

There are 10 targets to paint thus the total area to paint is 5.887 square feet.

Now for the read area : the read area is the total target's area minus the white area.
Total area of one target : pi*(3+3+3)^2=81*pi~254.34 sq in=1.766 square feet
Hence for 10 targets the total area is 17.66 square feet.
Thus the total area to paint in red is 17.66-5.887=11.773 square feet

You can paint 16 square feet of each paint, hence you have enough paint to do your work.

The first option would be correct if it were one half and not one