In how many ways can a committee of 5 people be chosen from a total of 30 possible people?

 142506

Step-by-step explanation:

Given : The total number of choices for people in committee = 30

The number of people need to be chosen =5

Since , here order doesn't matter, so we use combination.

The combination of r things taking from n at a time is given by :-

Now, the number of possible combinations of 5 people be chosen from a total of 30 possible people :-

Hence, the committee can be made in 142506 ways.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5