What is the solution to the system of equations?
x=3y+5
x-4y=3
( , )

X=3y+5
x-4y=3
3y+5-4y=3
5-y=3
y=5-3
y=2
x=3·2+5
x=6+5
x=11

(2;11)

So one way is to subsitute

from the first equation we know that x=3y+5
so we subsitte 3y+5 for x in the second equation

(3y+5)-4y=3
3y+5-4y=3
combine like terms
5-y=3
subtract 5 from both sdies
-y=-2
multiply -1
y=2

subsitute 2 for y

x=3(2)+5
x=6+5
x=11

x=11
y=2
(11,2)