Write an equation in slope-intercept form of the line through point p(–10, 1) with slope –5.

a. y=-5x-49
b. y-1=--5(x+10)
c. y-10=-5(x+1)
d. y= -5x+1

Hello:
the equation is : y = ax+b  a is the slope   : a =-5
     

a = -5         y=-5x+b
the line that passes through (-10,1) :1 = (-5)(-10)+b
b =-49
 the equation is :  y  = -5x-49... ( answer :  A. y=-5x-49 )

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

1.3 million hoops i believe