If the equation of a circle is (x - 2)2 + (y - 6)2 = 4, it passes through point
(2, 8)
(5, 6)
(-5, 6)
(2, -8)

circle passes through (2,8)

Step-by-step explanation:

Given :  equation of a circle is (x - 2)² + (y - 6)²= 4.

To find : It passes through point .

Solution : We have given that  (x - 2)² + (y - 6)²= 4.

Standard form of circle is  (x - h)² + (y - k)²= r².

Where , (h,k)  is center point and r is radius.

Rewrite the given equation in standard form of circle  (x - 2)² + (y - 6)²= 2².

Here, h = 2 and k = 6  , radius = 2.

We can plot points with the help of radius = 2 ,through which points circle passes

                                     center ( 2,6)

                                     up ( 2 , 6+2) = (2,8)

                              Down   ( 2, 6-2 ) = (2,4)

                               Left  (2-2,6) = (0,6)

                             Right (2+2 , 6) = = (4,6)

Therefore, circle passes through (2,8).

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the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.