6w^2-11w-35

i need to factor the problem

Hello :
 6w²-11w-35
Δ = b²-4ac    a = 6        b= -11          c = -35
Δ = (-11)² -4(6)(-35) =121 +840 = 961=31²
w1 = (11-31)/12 = -20/12 = -5/3
w2 = (11+31)/12 =42/12 =7/2
 6w²-11w-35 =6(w-w1)(w-w2) = 6(w+5/3)(w-7/2)
                                               = 1/2(6w+10)(2w-7)

 6w²-11w-35  =(3w+5)(2w-7)

6(2x + 5y)6 (2x) = 12x6 (5y) = 30y12x + 30y