triangle abc with vertices a(-2,-2) b(-3,1) c(1,1) is translated by
(x, y) > (x -1, y+3). then the image, triangle a'b'c', is translated by
(x, y) > (x + 4, y-1) resulting in a''b''c''.
find the coordinates for the vertices of triangle a"b"c".
write a rule for 1 translation that maps triangle abc to triangle a"b"c". i do not understand you!

Oh ok
so for example B(x,y)->B(-3,1) x=-3,y=1
it said to translate (x-1,y+3) go left 1 unit + go up 3 unit -> B'(-3-1,1+3)=B'(-4,4) then you do the same thing if it asks you to do it again

A'(-2-1,-2+3)->A'(-3,1)
B'(-4,4)
C'(1-1,1+3)->C'(0,4)

then translate again to get A"B"C" (x+4,y-1) go right 4 unit + go down 1 unit
A"(-3+4,1-1)->A"(1,0)
B"(-4+4,4-1)->B"(0,3)
C"(0+4,4-1)->C"(4,3)

2+2-9-$29: ! 3$3$282! 2! 2