What is the value of x? round your answer to the nearest tenth if necessary.

right triangle whose two legs measure fourteen and x, and whose hypotenuse measures twenty

To solve this we'll use Pythagorean theorem.
Which is a^2+b^2=c^2

C is the hypotenuse, and a or b can be either leg.
Because we start with the hypotenuse we rearrange the equation to be c^2-a^2= b^2

-A and B are universal, so you can plug them into either one-

So
20^2-14^2=b^2
Take note that b is raised to the 2nd power
So in order to undo it we'll square root it

To solve this we'll use Pythagorean theorem.
Which is a^2+b^2=c^2

C is the hypotenuse, and a or b can be either leg.
Because we start with the hypotenuse we rearrange the equation to be c^2-a^2= b^2

-A and B are universal, so you can plug them into either one-

So
20^2-14^2=b^2
Take note that b is raised to the 2nd power
So in order to undo it we'll square root it

√(204=14.282856857
We then go to the tenth place, So the answer is rounded to 14.3

X=14.3