The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. the center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.

I think the diameter is 6 meters and the height above ground is 8 meters both at the center

rick would give her the best deal as he will charge $8.88 per hour

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116