Between x = 0 and x = 1, which function has a smaller average rate of change than y = 3x ? a) y = 8x + 2 b) y = 3x + 2 eliminate c) y = 2x

The average rate of change of a function over a closed interval [a,b] is given with : f(b)-f(a)/(b-a).

The interval in our case is [0,1]. The average rate of change fot the function y=3x is:

(3*1-3*0)/(1-0)=3/1=3

We will calculate the average rate of changes of all listed functions:

A)    y = 8x + 2

(8*1+2) – (8*0+2)/(1-0)=(10-2)/1=8/1=8

B)     y = 3x + 2

(3*1+2) – (3*0+2)/1=5-2=3

C)    y = 2x

(2*1) – (2*0)/1=2

So, smaller average rate of change has the function y=2x.

step-by-step explanation:

you can't solve x because it is 2 linear equation and you only have one equation