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Mathematics, 03.12.2019 01:31 ghernadez

Simplify. consider all the cases.
example:
xβˆ’5=

xβˆ’5, if x> 5
0, if x=5
5βˆ’x, if x< 5

2x+7

a) if x > , then 2x + 7 =
b)if x = , then 2x + 7 =
c) if x < , then 2x + 7 =
(xβˆ’4)+7

if x > , then (x βˆ’ 4) + 7 =
if x = , then (x βˆ’ 4) + 7 =
if x < , then (x βˆ’ 4) + 7 =

7βˆ’(xβˆ’7)

if x > , then 7 βˆ’ (x βˆ’ 7) =
if x = , then 7 βˆ’ (x βˆ’ 7) =
if x < , then 7 βˆ’ (x βˆ’ 7) =

7βˆ’(12βˆ’x)

if x > , then 7 βˆ’ (12 βˆ’ x)=
if x = , then 7 βˆ’ (12 βˆ’ x =
if x < , then 7 βˆ’ (12 βˆ’ x)=

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You know the right answer?
Simplify. consider all the cases.
example:
xβˆ’5=

xβˆ’5, if x> 5
0,...
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