In the xy-coordinate plane, the graph of the equation y=2x^2-12x-32 has zeros at x=d and x=e, where d> e. the graph has a minimum at (f,-50) what are the vaules of d, e,and f?

To find the zeroes  solve fro x:-

2(x^2 - 6x - 16) = 0

2(x - 8)(x + 2) = 0

x =  {8, -2
 so d = 8 and e = -2

the x coordinate of the minimum value = - b / 2a =  12/ 2*2  =  3

f = 3

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%