The photography club decided to go on a field trip to the andy warhol museum. they had to break into smaller groups once they got there. the first group had 25 students and 2 teachers. their cost was $97.50. the second group had 32 students and 3 teachers. their cost was $127. what is the cost of each student and each teacher?

part a: define your variables

part b: write a system of equations to represent this situation

part c: solve the system of equations you wrote in part b.

part d: interpret what your answer means in context to this situation.

A)
Let x represent the cost of 1 student, and y the cost of 1 teacher.

B)
In the first group, there's 25 students and 2 teachers. Their total cost is $97.50
So 25x + 2y = 97.50
In the second group, there's 32 students and 3 teachers. Their total cost is $127
So 32x + 3y = 127

We get the following system of equations:
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)

C)
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)

In equation (1)
25x + 2y = 97.50
25x + 2y - 2y = 97.50 - 2y
25x = 97.50 - 2y
25x / 25 = 97.50/25 - 2y/25
x = 3.9 - (2/25)y

In equation (2), let's replace x by its algebraic value
32x + 3y = 127
32(-2/25y + 3.9) + 3y = 127
11/25y + 124.8 = 127
11/25y + 124.8 - 124.8 = 127 - 124.8
11/25y = 2.2
(11/25y) / (11/25) = 2.2 / (11/25)
y = 5

x = -2/25y + 3.9
x = -2/25 * 5 + 3.9
x = 3.5

So the cost of each student is $3.5, and the cost of each teacher is $5.

Hope this helps! :)

Bis the correct answer