a bucket hold holds 10 white golf balls, 3 pink golf balls, and 5 yellow golf balls. jason selects 1 golf ball from the bucket at random.
what is the probability that the golf ball he selects is white or pink?
a.5/54
b.13/5
c.5/13
d.13/18

 The correct option is (D)

Step-by-step explanation:  Given that a bucket hold holds 10 white golf balls, 3 pink golf balls, and 5 yellow golf balls. Jason selects 1 golf ball from the bucket at random.

We are to find the probability that the golf ball he selects is white or pink.

Let, 'A' denotes the event that the golf ball that Jason selects is either white or pink.

Then, n(A) = 10 + 3 = 13.

Let, 'S' denotes the sample space for the experiment.

Then, n(S) = 10 + 3 + 5 = 18.

Therefore, the probability that the probability that the golf ball Jason selects is white or pink is given by

Thus, the required probability is

Option (D) is correct.

the one below it is a function

yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36