At a carnival game, you randomly throw two darts at a board with 15 balloons and break two balloons. what is the probability that both the balloons you break are purple? write your answer as a fraction or percent rounded to the nearest tenth.

It doesn't sa how many balloons are purple but ill still help u

This is an dependent variable and let x stand for the number of purple balloons

the chance that u hit a purple with teh first dart is x/15

The chance that u hit a purple with the second dart is x-1/14

the answer is x/15 times x-1/14

2/35

Step-by-step explanation:

with 4 purple balloons, the probability of the first throw is 4/15. if you hit purple after the first throw, the probability is 3/14 (you lose one purple balloon which leaves 3 purple balloons and 14 in total)

you multiply 4/15 and 3/14 to get 12/210, which simplifies to 2/35

-13

step-by-step explanation:

f(x)=2x-5 for f(-4)

f(-4)   means let x=-4

f(-4) = 2(-4) -5

f(-4) =-8-5

      = -13

answer: a

step-by-step explanation: