The sum of the first n consecutive even numbers can be found using s = n2 + n, where n ≥ 2.
what is the value of n when the sum is 156?

Value of n when sum is 156 is 12

Step-by-step explanation:

Given: function to find sum of first n consecutive even numbers, S = n² + n where n ≥ 2

To find: value of n when Sum = 156

Consider, the function

S = n² + n

156 = n² + n

n² + n - 156 = 0

n² + 13n - 12n - 156 = 0

n ( n + 13 ) - 12 ( n + 13 ) = 0

( n + 13 )( n - 12 ) = 0

So, n + 13 = 0    nd     n - 12 = 0

⇒ n = -13    and  n = 12

n cannot be less than 2, So, value of n = 12

Therefore, Value of n when sum is 156 is 12

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

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i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

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