In a survey taken in july 1985, of the 50 households randomly surveyed from across the united states, the proportion of households having a personal computer was determined to be 11%. the u. s. government census data taken in august 1985 suggested that 11.7% of households in the united states had a personal computer. which statement(s) below support the small discrepancy between the sample proportion of households having a personal computer in july 1985 and the population proportion of households having a personal computer in august 1985?

 I.The sample size was too small.

II.The sample was not truly random.

III.The data from July 1985 to August 1985 changed substantially.

IV.The sample statistic is nearly equal to the population parameter and will never be exactly equal.

A. Only statements I, II, and III support the discrepancy.

B. Only statements I and III support the discrepancy.

C. Only statements I and IV support the discrepancy.

D. Only statement IV supports the discrepancy.

I think the answer is letter d. only statement IV supports the discrepancy. In the problem, it shows there that the survey happened in July 1985 was just a sample proportion of the family that uses a computer at home. So, the sample survey is nearly equal to the result of in August 1985 data, but will never be exactly equal

step-by-step explanation:

divide, then simplify your answer.

1. make -15.66 ÷   5.8 a fraction. then divide.

2. simplify.  

3. final answer.  

i use my brain for prombles like this maybe you could try it

step-by-step explanation: