Acylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown. if the basin is completely filled with water, how much water will it hold? round the answer to the nearest tenth of a foot.

The formula for solving the volume of a cylindrical basin is equal to V=pi*r²*h where "h" represents the height and "r" for the radius. Hence, in the given problem we have h=2ft and r=diameter/2.
r=5/2
r=2.5 ft
Solving for the volume:
V=3.1416*2.5²*2
V=39.27 cubic feet
If 1 cubic feet can hold 7.5 gallons, therefore the cylindrical basin can hold
#gallon=39.27*(7.5/1)
#gallon=294.525 gallons