Aball is thrown from a height of 40 meters with an initial downward velocity of 10 m/s. the balls height h (in meters) after t seconds is given by the following.

h = 40 - 10t - 5t^2

how long after the ball is thrown does it hit the ground?

round to nearest hundredth

0=40-10t-5t^2
t^2+2t-8=0
(t+4)(t-2)=0
t=-4 (not a solution) or t=2
after 2 seconds

First, set h (height) to 0, since that is the height we'll be solving for (at the ground). Factor the right side of the equation and set each individual binomial equal to zero. Solve for x in both equations and you should be left with a negative answer and a positive one. There is no negative time, so choose the answer that is positive.

The answer would be choice b

Answers4.) -1/205.) -1/406.) -55/127.) -3/4