Solve the equation:
12=19-√3x-11

     Original equation 
     12 = 19-√3x-11

     Isolate
     √3x-11 = -12+19

      Tidy up 
     √3x-11 = 7

     Raise both sides to the second power
     (√3x-11)2 = (7)2

     After squaring 
     3x-11 = 49

     Rearranged equation
      3x  -60 = 0

     Add  60  to both sides
      3x  = 60

     Divide both sides by 3
     A possible solution is :
     x = 20

     Original equation, root isolated

     √3x-11 = 7

     Plug in 20 for  x 
      √3•(20)-11 = 7
      Simplify
      √49 = 7
     Solution is: 
      x = 20

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the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: