In a prize drawing at a fundraiser, you choose three different numbers from 1 to 8. how many ways are there to choose three numbers?

If numbers cannot be repeated :

8 * 7 * 6

If numbers can be repeated :

8 * 8 * 8

The logic is that we have 8 different possibilities for the first digit. Then each of those 8 possibilities have 8 (or 7 if no repeats) for the second digit. Then each of those possibilites have 8(or 6 if no repeats) for the third digit.

55. i don’t no. but zhongshan