One number is 2 less than a second number. twice the second number is 16 more than 4 times the first. find the two numbers.

Let the numbers be x and y

x= y-2 (1)
and, 2y = 16 + 4x (2)

putting the value of x from (1) in (2),

2y = 16 + 4x
=> 2y = 16 + 4(y-2)
=> 2y = 16 + 4y - 8
=> 2y = 8 + 4y
=> 2y - 4y = 8
=> -2y = 8
=> y =-8/2
=> y= -4

and x = -4-2 = -6

hence , in short the numbers are -2 and -4

Idon’t know actually i’m in 5th grade and don’t know