4) landon is standing in a hole that is 6.5 m deep. he throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. the path of the rock can be modeled by the equation y=-0.05x^2+4.5x-6.5, where x is the horizontal distance of the rock, in meters, from landon and y is the height, in meters, of the rock above the ground. how far horizontally from landon will the rock land? round your answer to the nearest hundredth of a meter. (1 point)

a. 82.03 m <
b. 6.50 m
c. 90.00 m
d. 88.53 m

The rock will land 88.53 horizontally far from Landon.

Step-by-step explanation:

The path of the rock can be modeled by the equation:  

Where x is the horizontal distance of the rock, in meters, from landon and y is the height, in meters, of the rock above the ground.

Now we are supposed to find How far horizontally from landon will the rock land

when the rock land so y becomes 0

So, substitute y =0 is the given equation.

Use quadratic formula :

Substitute a = -0.05

b = 4.5

c= -6.5

So,

Thus It will be 88.53m horizontal distance from Landon when it strikes the ground.

The rock will be 1.47m horizontal distance from Landon where it exits the hole.

Hence Option D is correct.

The rock will land 88.53 horizontally far from Landon.

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !