Plotting at least 3 points y=2/3x-5

First you must plot one point on the y-axis. This point will be -5 because the y-intercept is a -5. Then you look at the slope. This is the number in front of the x. The numerator tells you how far up or down to go and the denominator tells you how far left or right to go. Because the slope is positive, we will go 2 points up from -5, and 3 points right from that. Plot your point. Then do the same thing from there. 2 up and 3 right and so on.

Y = 2/3x - 5
y + 5 = 2/3x - 5 + 5
3/2(y + 5) = 2/3x · 3/2
3/2y + 7 1/2 = x
y = 2/3(3/2y + 7 1/2) - 5
y = y + 5 - 5
y = y + 0
-y  -y     
0y = 0
 0     0
  y = 0
0 = 2/3x - 5
+5          +5
3/2 · 5 = 2/3x · 3/2
7 1/2 = x
(x, y) = (7 1/2, 0)

Skew lines(segments) are lines(segments) in 3 dimensions that do not intersect the given segment and are not parallel to it.  ae, bf, eg, and fh are your skew segments.  i hope that : )