The graph of a linear equation contains the points (3,11) and (-2,1). which point also lies on the graph?

The choices were not given but same question was retrieved from another source with the following choices: (2,1), (2,4), (2,6), (2,9). The most accurate way to verify if a point lies on the graph of the equation containing (3, 11) and (-2, 1) is to actually find the eqution first. For this, we need the points' slope, m, which is basically the rate of the difference of the y values over the x values. For this case, it's m = (11 - 1)/ (3 - -2) = 10/5 = 2 Now that we have the slope, we can write the general equation as (y - y1) = m(x- x1) We can choose either of the points for x1 and y1. So, we now have (y - 1) = 2(x - -2) y -1 = 2x + 5 y = 2x + 5 Now that we have the equation, y = 2x + 5, we can check which of the given points satisfy this. Since each of the choices have 2 as the x-coordinate, we can substitute this and look for y. y = 2(2) + 5 = 9 Therefore, the point lying in the same line is (2, 9).

Think of it as five or above give it a shove. change the 5 or above to the right to a zero and add one to the number on the left.