Formulate the quadratic function that contains the points (-1,4), (0,2) and (2,4).

f(x) = x2 + x + 2
f(x) = x2 + x - 2
f(x) = x2 - x + 2
f(x) = x2 - x - 2

Step-by-step explanation:

Quadratic equation form :   --1

We are given points :(-1,4), (0,2) and (2,4).

Substitute the point (0,2) in the quadratic equation.

Thus the value of c is 2

Substitute the value of c in 1

Thus equation becomes:   --2

Now substitute the point (-1,4) in 2

   ---3

Now substitute point (2,4) in 2

  --4

Now solve 3 and 4 to find the value of a and b

Substitute the value of a from 3 in 4

Substitute the value of b in 3

Thus a = 1, b =-1 and c = 2

Substitute the values in 1

Thus the quadratic function that contains the points (-1,4), (0,2) and (2,4) is  

Hence Option 3 is correct.

70

step-by-step explanation: