Johnny uses a wheelbarrow to move planting soil to a delivery truck. the volume of planting soil that fits in the wheelbarrow measures 2 feet by 3feet by 1.5 feet. the delivery truck measures 11 feet by 8 feet and is 6 feet tall. johnny puts soil in the delivery truck until its 70% full. what is the minimum number of times johnny needs to use the wheelbarrow until the truck is 70% full?

41 times.

Step-by-step explanation:

We have,

A delivery truck measures 11 feet by 8 feet and is 6 feet tall.

⇒ Volume of the truck = 11 × 8 × 6 = 528 ft³,

Now, the volume of planting soil that fits in the wheelbarrow measures 2 feet by 3 feet by 1.5 feet.

⇒ Volume of planting soil = 2 × 3 × 1.5 = 9 ft³,

Let n be the number of times johnny needs to use the wheelbarrow until the truck is 70% full,

⇒ Volume of planting soil × n = 70 % of the volume of the truck

Hence, the minimum number of times johnny needs to use the wheelbarrow until the truck is 70% full is 41.

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length