Mathematics, 28.01.2020 16:43 forschoolok123456789

In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving that triangle rst is congruent to triangle rsq given that rs ⊥ st, rs ⊥ sq, and ∠str ≅ ∠sqr. submit the entire proof to your instructor. given: rs ⊥ st rs ⊥ sq ∠str ≅ ∠sqr prove: △rst ≅ △rsq statement 1. rs ⊥ st, rs ⊥ sq, ∠str ≅ ∠sqr 2. 3. 4.△rst ≅ △rsq reason 1. 2. 3. 4.

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Answers

I see the solution in three steps.
1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
2.) RS≅RS | Reflexive Property
3.) △RST ≅ △RSQ | AAS Triangle Congruence Property
In a word processing document or on a separate piece of paper, use the guide to construct a two colu

In a word processing document or on a separate piece of paper, use the guide to construct a two colu

Answer from: 1thousandwishes

Give the statement: $RS \perp ST$ , $RS \perp SQ$ and

$\angle STR \cong SQR$

Perpendicular means if a line meeting another at a right angle or 90°

In Δ RST and Δ RSQ

$RS \perp ST$ [Given]

$RS \perp SQ$

By definition of perpendicular;

$\angle RST \cong \angle RSQ =90^{\circ}$ [Angle]

$\angle STR \cong SQR$ [Angle] [Given]

Reflexive property states that a value is equal to itself.

$RS \cong RS$ [Side] [Reflexive property ]

AAS(Angle -Angle -Side] Postulates states that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then the two triangles are congruent.

Then, by AAS postulates;

$\triangle RST \cong \triangle RSQ$

Two column proof:

Statement Reason

1. $RS \perp ST$ , Given

$RS \perp SQ$

$\angle STR \cong SQR$

2. $\angle RST \cong \angle RSQ =90^{\circ}$ def. of perpendicular

3. $RS \cong RS$ by Reflexive property

4. △RST ≅ △RSQ AAS postulates.

Answer from: johannah51

Give the statement: $RS \perp ST$ , $RS \perp SQ$ and

$\angle STR \cong SQR$

Perpendicular means if a line meeting another at a right angle or 90°

In Δ RST and Δ RSQ

$RS \perp ST$ [Given]

$RS \perp SQ$

By definition of perpendicular;

$\angle RST \cong \angle RSQ =90^{\circ}$ [Angle]

$\angle STR \cong SQR$ [Angle] [Given]

Reflexive property states that a value is equal to itself.

$RS \cong RS$ [Side] [Reflexive property ]

Then, by AAS postulates;

$\triangle RST \cong \triangle RSQ$

Two column proof:

Statement Reason

1. $RS \perp ST$ , Given

$RS \perp SQ$

$\angle STR \cong SQR$

2. $\angle RST \cong \angle RSQ =90^{\circ}$ def. of perpendicular

3. $RS \cong RS$ by Reflexive property

4. △RST ≅ △RSQ AAS postulates.

Answer from: Quest

step-by-step explanation:

Answer from: Quest

Absolute value graph shifted point 5 up

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