Imade a fort for my pet porcupine by connecting two boxes. the first box is 10 meters long, 7 meters wide, and 5 meters high. the second box is 4 meters long, 10 meters wide, and 8 meters high. how many cubic meters of space does my porcupine have to play in his fort?

First, let's find the volume of the two boxes.

V = lwhV=lwhV, equals, l, w, h

V=10\times7\times5V=10×7×5V, equals, 10, times, 7, times, 5

V= \blue{350} \text{ cubic meters}V=350 cubic metersV, equals, start color blue, 350, end color blue, space, c, u, b, i, c, space, m, e, t, e, r, s

V = lwhV=lwhV, equals, l, w, h

V=4\times10\times8V=4×10×8V, equals, 4, times, 10, times, 8

V= \pink{320} \text{ cubic meters}V=320 cubic metersV, equals, start color pink, 320, end color pink, space, c, u, b, i, c, space, m, e, t, e, r, s

Hint #22 / 3

Since my porcupine can play in both boxes, we need to add the volumes of the two boxes.

\blue{350}+\pink{320}=\green{670}350+320=670start color blue, 350, end color blue, plus, start color pink, 320, end color pink, equals, start color green, 670, end color green

Hint #33 / 3

My porcupine has \green{670}670start color green, 670, end color green cubic meters of space to play in his fort.  

670 is your answer i hoped this help please rate me thanks :)

Answer with Step-by-step explanation:

We are given that:

I made a fort for my pet porcupine by connecting two boxes.

The first box is 10 meters long, 7 meters wide, and 5 meters high.

The second box is 4 meters long, 10 meters wide, and 8 meters high.

We have to find how many cubic meters of space  porcupine have to play in his fort.

He can play inside the first box or the second box so, volume of two boxes represents the space porcupine has to play

   =10×7×5+4×8×10

  =  350+320

  = 670

Hence, porcupine can play in 670 cubic meters of space.

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.