The equation for a circle with center (h, k) is (x - h)2 (y - k)2 = r2. if a circle is modeled by the equation (x - 4)2 (y 6)2 = 49, what is the center of the circle?

By putting the equation in standard form the center is (4,6) and the radius is 7.

Iam thinking the answer is a.) knew

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !