E(-2,3) f (0,4) g (2,3) rhombus efgh has the coordinates shown. find the coordinates of point h.

Coordinates of point H is (0,2).

Step-by-step explanation:

Given the co-ordinates of rhombus which are E (-2,3), F (0,4), G (2,3). We have to find the coordinate of point H.

let coordinate of point H are (a,b).

Now, as diagonals of rhombus bisect each other.

⇒ O is the mid-point of HF and EG.

Hence, by mid-point formula

⇒ ,  

⇒ ,              

⇒ (a,b)=(0,2)

Hence, coordinates of point H is (0,2).

1 and 2

step-by-step explanation:

idk

step-by-step explanation: