The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to gravity, t is the time since launch, h(t) is the height of the projectile after time t, v0 is the initial velocity, and h0 is the initial height. the acceleration due to gravity is –9.8 m/s2. an object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters. which solution can be simplified to determine when the object will hit the ground?

The given:

Initial velocity of 20 m/s

Initial height of 60 m

Acceleration due to gravity of -9.8 m/s^2

Original formula:

H(t) = gt2 + v0t + h0

Derivation:

T= gt2 + v0t + h0 / h; where the yielding result will reveal the time when the object will reach the ground.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

the second option

step-by-step explanation: