If the the length of a rectangle is 5cm longer than twice the length of the width and the area if the rectangle is 403 square centimeters, what is the width?

X=width
(2x+5)=length
x(2x+5)=403
2x^2-5x-403=0
2x^2+26x-31x-403=0
2x(x+13)-31(x+13)=0
(x+13)(2x-31)=0
x=-13 or x=31/2
Since, our number cannot be negative, x=31/2

Have a nice day :D

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