Mr. clark claims that he has a coin that is weighted so that the probability of heads is 40%. to test this, his students flip the coin 200 times and calculate the relative frequency of heads and tails.

outcome heads tails
relative frequency 0.38 0.62
select from the drop-down menus to correctly complete each statement.
the relative frequency of heads is
a. reasonably close to
b. very different from
40%.
mr. clark's claim about the theoretical probability is likely to be
a. true
b. false

this means that the theoretical probability of tails is most likely
a.0.50
b.0.60
c.0.70

A) Option A

B) Option A

C) Option B

Step-by-step explanation:

A) Outcome of relative frequency was that the frequency of getting heads was 0.38 or 38% which is reasonably close to 40%.

B) This clears that the theoretical probability claimed by Mr. Clark was likely to be true

C) This means the theoretical probability of tails is most likely to be = 1 - 0.40 = 0.60 or 60% Therefore option B. is correct.

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)

w< 4

step-by-step explanation: