Asquare is drawn in a rectangular coordinate system such that its vertices are (-2, 2), (-2, -4), (4, -4), and (4, 2).

if a dart is thrown into the square without looking, what is the probability that it will land in the fourth quadrant? 1/9, 2/9, 4/9

So the base is from -2 to 4 and it's height is from -4 to 2

Overall the area is 6^2=36 u^2

The part in the fourth quadrant only has a base of 0 to 4 and a height from -4 to 0, so that area is only 4^2=16 u^2

So the probability of hitting the fourth quadrant is 16/36=4/9

40 because it’s just a little longer than 32 feet